02-07-2025, 12:28 PM
Out of simple routine, I created a for loop like this:
At first, I did not understand what was happening. break was not working. But there was not any error or even a warning. Then I realized: break is not a part of Basic. It never was.
The strange point is the absence of any error or warning. Either this was included in the grammar by error, or maybe because it is planned for inclusion.
I don't know.
Code:
for i = 0 to ubound(m)
if m( i ) = 0
break
end if
next
At first, I did not understand what was happening. break was not working. But there was not any error or even a warning. Then I realized: break is not a part of Basic. It never was.
The strange point is the absence of any error or warning. Either this was included in the grammar by error, or maybe because it is planned for inclusion.
I don't know.
-- Baltasar